The compressibility factor for a real gas at high pressure is-1-RT-Pb1-Pb-RT1-Pb-RT1

The correct option is B 1+Pb/RT( P + a/V^2 )(V b) = RT At high pressure a/V^2 can be neglected PV Pb = RT PV = RT + Pb PV/RT = 1 + Pb/RT Z = 1 + Pb/RT ...

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Standard XII

Chemistry

Molar and Specific Heat Capacity

The compressi...

Question

The compressibility factor for a real gas at high pressure is:

1 + \frac{R T}{P b}

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1 + \frac{P b}{R T}

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1 - \frac{P b}{R T}

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Solution

The correct option is C $1 + \frac{P b}{R T}$
$(P + \frac{a}{V^{2}}) (V - b) = R T$
At high pressure $\frac{a}{V^{2}}$ can be neglected
$P V - P b = R T$
$P V = R T + P b$
$\frac{P V}{R T} = 1 + \frac{P b}{R T}$
$Z = 1 + \frac{P b}{R T}$

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The compressibility factor for a real gas at high pressure is:

The correct option is C 1+PbRT(P+aV2)(V−b)=RT At high pressure aV2 can be neglected PV−Pb=RT PV=RT+Pb PVRT=1+PbRT Z=1+PbRT

The correct option is C $1 + \frac{P b}{R T}$
$(P + \frac{a}{V^{2}}) (V - b) = R T$
At high pressure $\frac{a}{V^{2}}$ can be neglected
$P V - P b = R T$
$P V = R T + P b$
$\frac{P V}{R T} = 1 + \frac{P b}{R T}$
$Z = 1 + \frac{P b}{R T}$