The kinetic energy of a body is -K- If one-fourth of its mass is removed and velocity nbsp- is doubled- its new kinetic energy is- K- 3 K- 4 K- 9 K4-

The correct option is B 3 K We have K.E = 12mv^2 where m is the mass and v is the velocity.Now,New mass =m m4= 34m New velocity ...

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Standard X

Physics

Kinetic Energy

The kinetic e...

Question

The kinetic energy of a body is 'K. If one-fourth of its mass is removed and velocity is doubled, its new kinetic energy is,

K

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3 K

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4 K

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\frac{9 K}{4}

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Solution

The correct option is B $3 K$
We have $K . E = \frac{1}{2} m v^{2}$

where $m$ is the mass and $v$ is the velocity.

Now,

New mass $= m - \frac{m}{4} = \frac{3}{4} m$

New velocity $= 2 v$

Now $K . E = K = \frac{1}{2} \times \frac{3}{4} m \times (2 v)^{2} = \frac{3 m v^{2}}{2} = 3 K$

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The kinetic energy of a body is 'K. If one-fourth of its mass is removed and velocity is doubled, its new kinetic energy is,

The correct option is B 3KWe have K.E=12mv2where m is the mass and v is the velocity.Now,New mass =m−m4=34mNew velocity =2vNow K.E=K=12×34m×(2v)2=3mv22=3K

The correct option is B $3 K$
We have $K . E = \frac{1}{2} m v^{2}$

where $m$ is the mass and $v$ is the velocity.

Now,

New mass $= m - \frac{m}{4} = \frac{3}{4} m$

New velocity $= 2 v$

Now $K . E = K = \frac{1}{2} \times \frac{3}{4} m \times (2 v)^{2} = \frac{3 m v^{2}}{2} = 3 K$