The mass of one atom of chlorine is

$\frac{1}{6.022 \times 10^{23}} g$

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$\frac{71}{6.022 \times 10^{23}} g$

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$\frac{35.5}{6.022 x 10^{23}} g$

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$71 u$

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Solution

The correct option is C
$\frac{35.5}{6.022 x 10^{23}} g$

One mole of Chlorine(Cl) atom has a mass of 35.5 g.
One mole of chlorine atom has Avogadro's number of atoms of chlorine = 6.023 X 10²³ atoms
Therefore, 6.023 X 10²³ atoms of chlorine have mass= 35.5 g
1 atom of chlorine has mass= $\frac{35.5 g}{6.023 X 10^{23}}$
Hence option (c) is correct.

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