The moment of inertia of a uniform rod of mass 0.50 kg and length 1 m is 0.10 ${\text{kg-m}}^2$ about a line perpendicular to the rod. Find the distance of this line from the middle point of the rod.

Length of the rod = 1 m, Mass of the rod = 0.5 kg Let at a distance d from the centre the rod is moving. Applying parallel axis theorem, the moment of inertia about the point

$\left(\frac{m{l}^2}{12}\right)+m{d}^2=0.10$

$\Rightarrow \frac{0.5\times l^2}{12}+0.5\times d^2=0.10$

$\Rightarrow \frac{1}{12}+d^2=0.2$

$\Rightarrow d^2=0.118$

$\Rightarrow d=0.342m$ from the centre