The number of gram molecules of oxygen in $6.02\times {10}^{24}$ CO molecule is

The correct option is (D) 5 g-molecule

Given :

No of CO molecules= $6.022\times {10}^{24}$

We know,

Number of oxygen atoms = Number of CO molecules= $6.022\times {10}^{24}$

$Numberofoxygenmolecule=\frac{1}{2}\times Numberofoxygenatoms=\frac{1}{2}\times 6.022\times {10}^{24}$

$=3.011\times {10}^{24}$

Number of g-molecule of $O_2$ molecules $=\frac{Noofmolecules}{Avogadr{o}^{\prime }sNo}=\frac{3.011\times {10}^{24}}{6.022\times {10}^{23}}=5g-molecule$

(Note: mole also called gram-molecule.)