The number of molecules present in 16 g of SO2 is 3-1023-

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Molecular Weight

The number of...

Question

The number of molecules present in 16 g of SO₂ is 3×10²³.

True

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False

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Solution

The correct option is B False
Step-1: Calculate the molecular weight of Sulphur dioxide
The gram atomic weight of Sulphur=32 gm
The gram atomic weight of Oxygen= 16 gm
The gram molecular weight of Sulphur dioxide (SO₂)= Gram atomic weight of Sulphur+ 2(Gram atomic weight of Oxygen)
The gram molecular weight of Sulphur dioxide (SO₂)= 32gm + 2(16gm)
The gram molecular weight of Sulphur dioxide (SO₂)= 64 gm
Step-2: Calculate the number of molecules
64 g of Sulphur dioxide contain molecules of Sulphur dioxide= $6.023 \times 10^{23}$
1 g of Sulphur dioxide contains molecules of Sulphur dioxide= $\frac{6.023 \times 10^{23}}{64}$
16 g of Sulphur dioxide contain molecules of Sulphur dioxide= $\frac{6.023 \times 10^{23}}{64} \times 16 = 1.5 \times 10^{23}$
Therefore, the given statement is false.

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The number of molecules present in 16 g of SO2 is 3×1023.

The number of molecules present in 16 g of SO₂ is 3×10²³.