The potential at a point due to a charge of $5\times {10}^{-7}C$ located $10cm$ away is:

Q. The potential at a point due to a charge of $5\times {10}^{-7}C$ located $10cm$ away is $4.5\times {10}^{4}V$. The work done in bringing a charge of $4\times {10}^{-9}C$ from infinity to that point is:

Q. Calculate the potential at a point due to a charge of $4\times {10}^{-7}C$ located at $0.09m$ away.

Q. The potential at a point due to a charge of 5 x ${10}^{-7}$ C located 10 cm away is:

Q. Two point charges $4\mu C$ and $9\mu C$are separated by a distance of 50 cm. The potential at the point between them where the field has zero strength is

Q. Construct two tangent to a circle of radius $3.5$ cm from a point $4.5$ cm away from the circle.