The probability of obtaining an even prime number on each die, when a pair of dice is rolled is

\frac{1}{36}

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\frac{1}{3}

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\frac{1}{12}

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Solution

The correct option is A $\frac{1}{36}$
Sample space when pair of die are thrown,

$S = ⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩ \begin{matrix} (1, 1) (1, 2) (1, 3) (1, 4) (1, 5), (1, 6), (2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6) (3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6) (4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6) (5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6) (6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6) \end{matrix} ⎫ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎬ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎭$

$n (S) = 36$

Let $E$ be the favourable event of gettng even prime number on both die

$E = (2, 2)$

Probability of getting even prime number on both die

$P (E) = \frac{1}{36}$

$∴$ Probability of obtaining an even prime number on each die $= \frac{1}{36}$

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Similar questions

Q. Find the probability of obtaining an even prime number on each die , when a pair of dice is rolled ?

The probability of obtaining an even prime number on each die, when a pair of dice is rolled is

(A) 0 (B) (C) (D)

Choose the correct answer.
The probability of obtaining an even prime number on each die when a pair of dice is rolled is
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Q. E is the event of 'getting an even prime number' on rolling a dice once. The probability of it's complementary event is .

If two different dice are rolled together, the probability of getting an even number on both dice, is:

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