The reactant which is entirely consumed in reaction is known as limiting reagent. In the reaction $2A+4B⟶3C+4D$, if $5$ moles of $A$ reacts with $6$ moles of B then, which is the limiting reagent?

The correct option is B $B$
The balanced reaction is as follows:
$2A+4B\to 3C+4D$

No. of moles given: $5,6$

Stoichiometry coefficients given: $2,4$

Ratio of moles given and stoichiometry coefficients:

For A: $\frac{5}{2}$ = $2.5$

For B: $\frac{6}{4}$ = $1.5$

As $1.5$ is lower than $2.5$, B is limiting reagent as it will be consumed first.