Ways of Representing the Concentration of a Solution
The reaction
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Question
The reaction Cl2+S2O32−+OH−⟶SO42−+Cl−+H2O Starting with 0.15 mole Cl2,0.010 moleS2O32−and 0.30 mole OH−, mole of Cl2 left in solution will be
A
0.11
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B
0.01
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C
0.04
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D
0.09
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Solution
The correct option is B 0.11 4Cl2+S2O32−+10OH−⟶2SO42−+8Cl−+5H2O limiting reagent is S2O32− 1 mole of S2O32− react with 4 mole Cl2 so, 0.01 mole S2O32−=0.01×4=0.04moleCl2 moles of Cl2 left=0.15−0.04=0.11