The relation 3t=$\sqrt{3x}$+6 describes the displacement of a particle in one direction where x is in metres and t in sec. The displacement, when velocity is zero, is

Q. The relation$3t=\sqrt{3x}+6$describes the displacement of a particle in one direction where x is in metres and t in sec. The displacement, when velocity is zero, is

Q. The relation $3t=\surd 3x+6$ describes the displacement of a particle in one direction where $x$ is in meters and $t$ in $sec$. The displacement, when velocity is zero, is

Q.

The displacement x of a particle moving in one dimension is related to time t by the equation $t=\sqrt{x}+3$ where x is in metres and t in seconds. The displacement of the particle when its velocity is zero is

Q. The distance $x$ of a particle moving in one-direction, under the action of a constant force is related to time by equation
$t=\sqrt{x}+3$
where $x$ is in metres, $t$ is in seconds.
Find the displacement of the particle when its velocity is zero.

Q. The displacement $x$ of a particle moving in one dimension under the action of a constant force is related to time $t$ by the equation $t-3=\sqrt{x}$ where $x$ is in metres and $t$ is in seconds. Find the displacement of the particle when its velocity is zero.