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Equivalent, Molar Conductivity and Cell Constant

The resistanc...

Question

The resistance of a $N / 10$ KCl solution is 245 ohms. The specific conductance and the equivalent conductance of the solution if the electrodes in the cell are 4 cm apart and each having an area of 7.0 sq. cm. are :

2.332 \times 10^{- 3} m h o c m^{- 1}, 23.32 m h o c m^{2} e q^{- 1}

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2.302 \times 10^{- 3} m h o c m^{- 1}, 21.22 m h o c m^{2} e q^{- 1}

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2.312 \times 10^{- 3} m h o c m^{- 1}, 22.12 m h o c m^{2} e q^{- 1}

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none of these

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Solution

The correct option is A $2.332 \times 10^{- 3} m h o c m^{- 1}, 23.32 m h o c m^{2} e q^{- 1}$
$f o r m u l a f o r t h e s p e c i f i c c o n d u c t a n c e (K) = \frac{1}{R} \times \frac{l}{a}$ .
$= \frac{1}{245} \times \frac{4}{7} K = 2.33 \times 10^{- 3} m h o c m^{- 1}$

$f o r m u l a f o r t h e e u i v a l e n t c o n d u c t a n c e (Λ) = K \times \frac{1000}{C} = 2.33 \times 10^{- 3} \times \frac{1000}{\frac{1}{10}} = 2.33 \times 10^{- 3} \times 10000 = 23.32 o h m^{- 1} c m^{2} / g r . e q . w t$
So answer is A

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Similar questions

The resistance of a N/10 KCl aqueous solution is 245 ohm. If the electrodes in the cell are 4 cm apart and area having 7 cm² each, the molar conductance of the solution will be

A 233

B 2.33

C 23.32

D 0.233

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Q. In a conductivity cell the two platinum electrodes, each of area 10 sq. cm. are fixed 1.5 cm apart. The cell contained 0.05 N solution of a salt. If the two electrodes are just half dipped into the solution which has a resistance of 50 ohms, the equivalent conductance of the salt solution will be:

Q. Resistance of a

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The resistance of a N/10 KCl solution is 245 ohms. The specific conductance and the equivalent conductance of the solution if the electrodes in the cell are 4 cm apart and each having an area of 7.0 sq. cm. are :

The correct option is A 2.332×10−3mhocm−1,23.32mhocm2eq−1formulaforthespecificconductance(K)=1R×la. =1245×47K=2.33×10−3mhocm−1formulafortheeuivalentconductance(Λ)=K×1000C=2.33×10−3×1000110=2.33×10−3×10000=23.32ohm−1cm2/gr.eq.wtSo answer is A

The resistance of a $N / 10$ KCl solution is 245 ohms. The specific conductance and the equivalent conductance of the solution if the electrodes in the cell are 4 cm apart and each having an area of 7.0 sq. cm. are :