The slope of - versus C was made against insulin concentration c- in gmL-1 and temperature 27-C- If nbsp-C is in litre-1 nbsp-and the slope of line obtained is 4-65 - 10-3-g-mL- which of the following are not the molar mass - in g mol-1 - of insulin-9-10-53-10-54-5-10-55-30-10-6

The correct options are A 9×10^5 B 3×10^5 C 4.5×10^5Osmotic pressure is given by π=CRT, C=wVM π=wVRTM,Where M is the molar mass of insulin ∴ slope=RTM=4.65×10^ ...

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Byju's Answer

Standard XII

Chemistry

Osmotic Pressure

The slope of ...

Question

The slope of $π$ versus $C$ was made against insulin concentration $c$ . in ${gmL}^{- 1}$ and temperature $27^{\circ} C$ . If $C$ is in ${litre}^{- 1}$ and the slope of line obtained is $4.65 \times 10^{- 3} \frac{g}{m L}$ , which of the following are not the molar mass $({in g mol}^{- 1})$ of insulin?

9 \times 10^{5}

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3 \times 10^{5}

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4.5 \times 10^{5}

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5.30 \times 10^{6}

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Solution

The correct options are
A $9 \times 10^{5}$
B $3 \times 10^{5}$
C $4.5 \times 10^{5}$
Osmotic pressure is given by $π = C R T$ , $C = \frac{w}{V M}$
$π = \frac{w}{V} \frac{R T}{M}$ ,Where M is the molar mass of insulin
$∴ s l o p e = \frac{R T}{M} = 4.65 \times 10^{- 6} g / L$
$\frac{0.0821 \times 300}{4.65 \times 10^{- 6}} = M = 5.30 \times 10^{6} g / m o l$

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The slope of π versus C was made against insulin concentration c. in gmL−1 and temperature 27 ∘C. If C is in litre−1 and the slope of line obtained is 4.65×10−3 gmL, which of the following are not the molar mass (in g mol−1) of insulin?

The correct options are A 9×105 B 3×105 C 4.5×105Osmotic pressure is given by π=CRT, C=wVM π=wVRTM,Where M is the molar mass of insulin ∴slope=RTM=4.65×10−6g/L 0.0821×3004.65×10−6=M=5.30×106g/mol