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Question

The smallest 5 digit number exactly divisible by 41 is:

A
1004
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B
10004
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C
10045
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D
10025
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E
None of these
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Solution

The correct option is B 10004
The smallest 5-digit number =10000
10000÷41 (Quotient=243; Remainder=37)
Required number =10000+(4137)
=10004.

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