The smallest number which when increased by 17 is exactly divisible by both 520 and 468 is

The correct option is C 4663
Here, first we need to find the smallest number which is exactly divisible by 520 and 468, then we have to subtract 17 from obtained result.
So smallest number divisible by 520 and 468 is the LCM (520, 468)
$520=2^3\times 5\times 13$
$468=2^2\times 3^2\times 13$
So, LCM(520, 468)- $2^3\times 3^2\times 5\times 13=4680$
Required answer = 4680 - 17 =4663
Hence, correct option is c