The speed of light in diamond is $125, 000$ $k m s^{- 1}$ . What is its refractive index ? (Speed of light in air = $3 \times 10^{8} m s^{- 1}$ ).

1 / 2.4

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2.4

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1.2

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Solution

The correct option is B $2.4$
According to Snell's Law: $\frac{n_{2}}{n_{1}} = \frac{v_{1}}{v_{2}}$ and R.I for air is $1$
Substituting, $\frac{n_{2}}{1} = \frac{3 \times 10^{8}}{1.25 \times 10^{8}}$
Therefore, $n_{2} = 2.4$

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Similar questions

Q. The speed of light in air is

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Q. The refracting index of diamond is 2.42 and the speed of light in air is

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Light enters from air into diamond which has a refractive index of 2.42. Calculate the speed of light in diamond. The speed of light in air is 3.0 x $10^{8} m s^{- 1}$ .

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The speed of light in diamond is 125,000 kms−1. What is its refractive index ? (Speed of light in air = 3×108ms−1).

The correct option is B 2.4According to Snell's Law: n2n1=v1v2 and R.I for air is 1Substituting, n21=3×1081.25×108Therefore, n2=2.4

The speed of light in diamond is $125, 000$ $k m s^{- 1}$ . What is its refractive index ? (Speed of light in air = $3 \times 10^{8} m s^{- 1}$ ).

The correct option is B $2.4$
According to Snell's Law: $\frac{n_{2}}{n_{1}} = \frac{v_{1}}{v_{2}}$ and R.I for air is $1$
Substituting, $\frac{n_{2}}{1} = \frac{3 \times 10^{8}}{1.25 \times 10^{8}}$
Therefore, $n_{2} = 2.4$