The structure of a mixed oxide is cubic close packed (ccp). The cubic unit cell of mixed oxide is composed of oxide ions. One-fourth of the tetrahedral voids are occupied by divalent metal A and the octahedral voids are occupied by a monovalent metal B. The formula of the oxide is

$A B O_{2}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$A_{2} B O_{2}$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$A_{2} B_{3} O_{4}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$A B_{2} O_{2}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D. $A B_{2} O_{2}$
Number of atoms in $C C P = 4 \Rightarrow O^{2 -}$
No. of tetrahedral voids $= 2 \times N = 2 \times 4 = 8$
No. of $A^{2 +} i o n s = 8 \times \frac{1}{4} = 2$
No. of octahedral voids = N = 4
No. of $B^{+} i o n s = 4$
Ratio $\Rightarrow O^{2 -} : A^{2 +} : B^{+} \Rightarrow 4 : 2 : 4 \Rightarrow 2 : 1 : 2$
Formula $\Rightarrow A B_{2} O_{2}$

Suggest Corrections

Similar questions

Q. Structure of a mixed oxide is cubic close packed

(c c p)

. The cubic unit cell of mixed oxide is composed of oxide ions. One fourth of the tetrahedral voids are occupied by divalent metal

A

and the octahedral voids are occupied by a monovalent metal

B

. The formula of the oxide is:

The structure of a mixed oxide is cubic closed packed (ccp). The cubic unit cell of mixed oxide is composed of oxide ions. One fourth of the tetrahedral voids are occupied by divalent mtal A and the octahedral voids are occupied by a monovalent metal B. The formula of the oxide is:

Q. Structure of a mixed oxide is cubic close-packed (CCP). The cubic unit cell of mixed oxide is composed of oxide ions. One fourth of the tetrahedral voids are occupied by divalent metal A and the octahedral voids are occupied by a mono-valent metal B. The formula of the oxide is ?

Q. The cubic unit cell of a mixed oxide is composed of oxide ions in a ccp arrangement. One fourth of the tetrahedral voids are occupied by divalent metal '

A

' and the octahedral voids are occupied by a monovalent metal '

B

'. The formula of the oxide is:

Join BYJU'S Learning Program

The structure of a mixed oxide is cubic close packed (ccp). The cubic unit cell of mixed oxide is composed of oxide ions. One-fourth of the tetrahedral voids are occupied by divalent metal A and the octahedral voids are occupied by a monovalent metal B. The formula of the oxide is

The correct option is D. AB2O2Number of atoms in CCP=4⇒O2− No. of tetrahedral voids =2×N=2×4=8 No. of A2+ ions=8×14=2 No. of octahedral voids = N = 4 No. of B+ions=4 Ratio ⇒O2−:A2+:B+⇒4:2:4⇒2:1:2 Formula ⇒AB2O2