The sum of three consecutive even numbers is 126. Find the numbers.

The correct option is C

40,42,44

Let the numbers be 2n + 2, 2n + 4 and 2n + 6. Then the sum is
2n + 2 + 2n + 4 + 2n + 6 = 6n + 12
6n + 12 = 126 (given)
6n = 126 – 12
6n = 114
n = 114 ÷ 6
n = 19
Therefore, the numbers are 40, 42, 44.