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Factors Affecting Vapour Pressure

The vapour pr...

Question

The vapour pressure of pure liquid solvent A is 0.80 atm. When a nonvolatile substance B is added to the solvent its vapour pressure drops to 0.60 atm. What is the mole fraction of component B in the solution?( If your answer is $x$ , then write $x \times 100$ ).

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Solution

Using Raoults law for lowering of vapour pressure.We get $\frac{P_{o} - P}{P_{o}} = x_{2}$
putting,Values of actual and lowered vapour pressure we get
$\frac{0.8 - 0.6}{0.8} = x_{2}$
where $x_{2}$ is the mole fraction
Ans-0.25

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