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Relation for Inverse Proportion

Question 64 T...

Question

Question 64

The variable x varies directly as y and x = 80 when y is 160. What is y when x is 64?

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Solution

If x varies directly as y.
$∴ \frac{x}{y} = k$ (constant)...(i)

If x=80 and y =160
$∴ \frac{x}{y} = \frac{80}{160} = \frac{1}{2} \Rightarrow k = \frac{1}{2}$

When x = 64, then from Eq(i),
$\frac{64}{y} = \frac{1}{2}$ [Putting the value of k]
$\Rightarrow y = 64 \times 2 = 128$

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