The volume of oxygen liberated from 15 ml of 20 volume $H_2{O}_2$ is

The correct option is B

300 ml

Quantity of $H_2{O}_2$ = 15ml and volume of $H_2{O}_2$ = 20

We know that 20 volume of $H_2{O}_2$ means 1 litre of this solution will give 20 litre at NTP

Since,oxygen liberated from 1000ml (1 litre) of $H_2{O}_2$ = 20 litre,

$\therefore$ Oxygen liberate from 15 ml = $\frac{20}{1000}\times 15$ = 0.3 litre = 300ml