Two equal and opposite charges of- 4-10-8 C when placed 2-10-2- cm -away- form a dipole- If this dipole is placed in an external electric field of 4-10-8 newton-coulomb- the value of maximum torque and the work done in rotating it through 180- will be- 64-10-4Nm -and-64-10-4J-32-10-4Nm -and-32-10-4J-32-10-4Nm -and-64-10-4J-64-10-4Nm -and-32-10-4J-

The correct option is C 32×10^ 4Nm and 64×10^ 4J Dipole moment p = 4 × 10^–8× 2 × 10^–4 = 8 × 10^–12 Cm Maximum torque = pE = 8 × 10^–12× 4 × 10^8 = 32 × 10^ ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Torque on a Dipole

Two equal and...

Question

Two equal and opposite charges of $4 \times 10^{- 8} C$ when placed $2 \times 10^{- 2} c m$ away, form a dipole. If this dipole is placed in an external electric field of $4 \times 10^{8}$ newton/coulomb, the value of maximum torque and the work done in rotating it through $180^{o}$ will be

64 \times 10^{- 4} N m a n d 64 \times 10^{- 4} J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

32 \times 10^{- 4} N m a n d 32 \times 10^{- 4} J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

64 \times 10^{- 4} N m a n d 32 \times 10^{- 4} J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

32 \times 10^{- 4} N m a n d 64 \times 10^{- 4} J

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is:C: $32 \times 10^{- 4} N m a n d 64 \times 10^{- 4} J$
Dipole moment, $= q \times 2 a = 4 \times 10^{- 8} C$ X $2 \times 10^{- 2} c m = 8 \times 10^{- 12} C m$
Maximum torque, $= 8 \times 10^{- 12} \times 4 \times 10^{8} = 32 \times 10^{- 4} N m$
Maximum work done in rotating through, $180^{o}$ , $= 2 p E = 2 \times$ $= 32 \times 10^{- 4} = 64 \times 10^{- 4} N m$

Suggest Corrections

Similar questions

Q. An electric dipole is placed at an angle of

30^{o}

with an electric field of intensity

2 \times 10^{5} N C^{- 1}

. It experiences a torque of

4 N m

. Calculate the charge on the dipole if the dipole length is

2 c m

Q. An electric dipole consisting of two opposite charges of

2 \times 10^{- 6} C

each, separated by a distance of 3 cm is placed in an electric field of

2 \times 10^{5} N / C

. The maximum torque on the dipole will be

Q. An electric dipole consisting of two opposite charges of magnitude

2 \times 10^{- 6} C

each, separated by a distance of 3 cm is placed in an electric field of

2 \times 10^{5} N / C

. The maximum torque on the dipole will be

Q. Two charges

+ 3.2 \times 10^{- 19}

and

- 3.2 \times 10^{- 19}

C placed

2.4 ˙ A

apart form an electric dipole. It is placed in a uniform electric field of intensity

4 \times 10^{5}

volt/m. The electric dipole moment is

Q. An electric dipole consist of two opposite charges each of magnitude

1 μ C

separated by a distance of

2 c m .

The dipole is placed in an external field of

10^{5} N/C

.The maximum torque on the dipole is:

Join BYJU'S Learning Program

Two equal and opposite charges of 4×10−8C when placed 2×10−2cm away, form a dipole. If this dipole is placed in an external electric field of 4×108 newton/coulomb, the value of maximum torque and the work done in rotating it through 180o will be

The correct option is:C: 32×10−4Nmand64×10−4J Dipole moment, =q×2a=4×10−8C X 2×10−2cm=8×10−12Cm Maximum torque, =8×10−12×4×108=32×10−4Nm Maximum work done in rotating through, 180o ,=2pE=2×=32×10−4=64×10−4Nm

Two equal and opposite charges of $4 \times 10^{- 8} C$ when placed $2 \times 10^{- 2} c m$ away, form a dipole. If this dipole is placed in an external electric field of $4 \times 10^{8}$ newton/coulomb, the value of maximum torque and the work done in rotating it through $180^{o}$ will be