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Question

Two identical charged spheres suspended from a common point by two massless strings of length l are initially a distance d(d<<) apart because of their mutual repulsion. The charge begins to leak from both the spheres at a constant rate. As a result the charges approach each other with a velocity v. Then as a function of distance x between them:

A
vx1/2
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B
vx1
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C
vx1/2
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D
vx
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Solution

The correct option is A vx1/2
Tsinθ=Kq2x2 ....(i)
Tcosθ=mg .....(ii)
or
tanθ=Kq2x2mg=xl(from the FBD); since d>>l
or
x3=Kq2mg (...iii)
x3q2
3x2dxdt2qdqdt
x2vq
Substituting the value of q from equation (iii).
vx12

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