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Standard XII

Physics

Law of Conservation of Mechanical Energy

Two masses of...

Question

Two masses of 4 kg and 5 kg are connected by a string passing through a frictionless pulley and are kept on a frictionless table as shown in the figure. The acceleration of 5 kg mass is

49 m/s²

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5.44 m/s²

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19.5 m/s²

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2.72 m/s²

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Solution

The correct option is B
5.44 m/s²

$a = \frac{m_{2}}{m_{1} + m_{2}} \times g = \frac{5}{4 + 5} \times 9.8 = \frac{49}{9} = 5.44 m / s^{2}$

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Two masses of 4 kg and 5 kg are connected by a string passing through a frictionless pulley and are kept on a frictionless table as shown in the figure. The acceleration of 5 kg mass is

The correct option is B 5.44 m/s2 a=m2m1+m2×g=54+5×9.8=499=5.44 m/s2

The correct option is B
5.44 m/s²

$a = \frac{m_{2}}{m_{1} + m_{2}} \times g = \frac{5}{4 + 5} \times 9.8 = \frac{49}{9} = 5.44 m / s^{2}$