Two plane mirrors are inclined to each other at an angle $\theta$. A ray of light is reflected first at one mirror and then at the other. The total deviation of the ray is

Q. Two vertical plane mirrors are inclined at an angle of ${60}^o$ with each other. A ray of light travelling horizontally is reflected first from one mirror and then from the other mirror. Then the resultant deviation is

Q. Two plane mirrors are inclined to each other at an angle of ${70}^0$. A ray is incident on one mirror at an angle $\theta$. The ray reflected from this mirror falls on the second mirror from where it is reflected parallel to the first mirror. Determine the value of $\theta$.

Q. Two vertical plane mirrors are inclined at an angle of ${60}^0$ with each other. A ray of light travelling horizontally is reflected first from one mirror and then from the other. The resultant deviation is

Q. Two plane mirrors $M_1$ and $M_2$ are inclined to each other at ${70}^{\circ }.$ A ray incident on the mirror $M_1$ at an angle $\theta$ falls on $M_2$ and is then reflected parallel to M, for

Q. Two plane mirrors are inclined at angle $\theta$. An optical ray $AB$ is incident on a mirror at an angle $2\theta$ with the mirror, as shown. The reflected ray from the second mirror, $CD$ is perpendicular to the incident ray. Find angle $q$-