Two point charges in air, at a distance of $20\text{cm}$ from each other, interact with a certain force. At what distance from each other should these charges be placed in oil of relative permittivity $5$ to obtain the same magnitude of force of interaction?

Q. Two point charges $q_1$ and $q_2$ are placed at a distance of $50\text{m}$ from each other in air, and interact with a certain force $F$. The same charges are now put in oil whose relative permittivity is $5.0$. Find the new force of interaction between them :

Q. Two point charges $q_1$ and $q_2$ are placed at a distance of 50 m from each other in air, and interact with a certain force. The same charges are now put in oil whose relative permittivity is 5. If the interacting force between them is still the same, their separation now is :

Q. Two point charges $q_1$ and $q_2$ are placed at a distance of $50\text{m}$ from each other in air, interact with a certain electrostatic force. If the medium is replaced with oil whose relative permittivity is $5$, then the interaction force between them is still the same. Now the separation between them is

Q. Two electrically charged particles, having charges of different magnitude, when placed at a distance d from each other, experience at the same distance from each other. What is the nature of new force between them? Is the magnitude of the force of interaction between them now more or less than F is?

Q. The electric force between two point charges separated by a certain distance in air is $F$ the distance at which they should be placed in a medium of relative permittivity $k$ so that the force remain the same is: