Two pure breeds of pea plant, one with yellow colour seeds (Y) and other with green colour seeds (y) are crossed to obtain $F_1$ generation. The genotypic ratio for the resulting ${F_2}^{}$ generation will be:

Q. A pea plant pure for yellow seed colour is crossed with a pea plant pure for green seed colour. In F${}_1$ generation, all pea plants were with yellow seeds. Which law of Mendel is applicable?

Q. A yellow seeded true breeding Pea plant is crossed with green seeded true breeding plant. $F_1$ plants were yellow seeded showing that allele for yellow colour is

Q. The pea plant with round shaped seeds with yellow colour seed (RRYY) crossed with another pea plant showing wrinkled shape with green cotyledons (rryy). The results of progeny in $F_2$ generation are produced in the following number.
i) Heterozygous for both shape and colour of seeds ......... number.
ii) Dominant for colour, but recessive for shape ........ number.
iii) Homozygous for both shape and colour of seeds ......... number.
iv) Heterozygous for seed shape only ........ number.

Q. A person first crossed pure-bred pea plants having round-yellow seeds with pure-bred pea plants having wrinkled-green seeds and found that only A-B type of seeds were produced in the $F_1$ generation. When $F_1$ generation pea plants having A-B type of seeds were cross-bred by self-pollination, then in addition to the original round-yellow and wrinkled-green seeds, two new varieties A-D and C-B type of seeds were also obtained.