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Question

Uncertainty in the position of an electron (mass=9.1×1031kg) moving with a velocity 300ms1 accurate upon 0.001% will be:

[h=6.63×1034Js]

A
19.2×102m
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B
5.76×102m
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C
1.92×102m
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D
3.84×102m
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Solution

The correct option is C 1.92×102m
According to Heisenberg's uncertainity principle

Δx×m×ΔV=h4π

Δx= uncertainty in the position

m=9.1×1031kg= mass of electron

ΔV=300×0.001100=0.003m/s

uncertainty in the velocity

h=6.62×1036Js= Planck's constant

Substitute values in the above formula

Δx×9.1×1031×0.003=6.62×10344×3.1416

Δx=1.92×102m

Hence, the correct option is C

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