The correct option is D 10
Step:1 Since 420 > 130 we apply the division lemma to 420 and 130 to get ,
420=130×3+30
Step:2 Since 30 ≠ 0 , we apply the division lemma to 130 and 30 to get
130=30×4+10
Step:3 Since 10 ≠ 0 , we apply the division lemma to 30 and 10 to get
30=10×3+0
The remainder has now become zero, so our procedure stops. Since the divisor at this Step is 10, the HCF of 420 and 130 is 10.