Vacant space in $b c c, f c c$ and simple cubic lattice respectively are:
[0.77 Mark]

46.6 %, 26 %

and

32 %

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26 %, 32 %

and

52.4 %

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68 %, 74 %

and

52.4 %

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32 %, 26 %

and

47.6 %

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Solution

The correct option is D $32 %, 26 %$ and $47.6 %$
The packing efficiency of $b c c$ lattice $= 68 %$
So, the vacant space $= 100 - 68 = 32 %$
The packing efficiency of fcc lattice $= 74 %$
So, the vacant space $= 100 - 74 = 26 %$
The packing efficiency of simple cubic lattice $= 52.4 %$
So, the vacant space $= 100 - 52.4 = 47.6 %$

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Similar questions

The correct order of the packing efficiency in different types of nuit cells is ............

(a) fcc < bcc < simple cubic (b) fcc > bcc > simple cubic

The vacant space in bcc lattice unit cell is

4.5 \circ A

3 \circ A

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