What is the balanced equation of ${\mathrm{SO}}_2+{\mathrm{O}}_2\to {\mathrm{SO}}_3$

Step 1: Define balanced chemical equation

• A balanced equation involves an equal number of atoms for each element on reactant and product side.

Step 2: Balance the given chemical equation

• The given reaction is as follows:-

${\mathrm{SO}}_2+{\mathrm{O}}_2\to {\mathrm{SO}}_3$

• On the reactant side, the number of sulphur atom$\left(\mathrm{S}\right)$ is $1$, and the number of oxygen atom$\left(\mathrm{O}\right)$ is $4$.
• On the product side, the number of sulphur atom$\left(\mathrm{S}\right)$ is $1$, and the number of oxygen atom$\left(\mathrm{O}\right)$ is $3$.
• So, to balance oxygen atoms, a coefficient of $2$ must be added infront of ${\mathrm{SO}}_2$, and ${\mathrm{SO}}_3$ in the reactant and product sides.

Step 3: Final balanced chemical equation

• The balanced chemical equation is as follows:-

$2{\mathrm{SO}}_2\left(\mathrm{g}\right)+{\mathrm{O}}_2\left(\mathrm{g}\right)\to 2{\mathrm{SO}}_3\left(\text{g}\right)$