What is the equivalent mass of Al2O3 in the following reaction? 4Al+3O2-----> 2Al2O3

Q. What is the equivalent mass of $A{l}_2{O}_3$ in the following reaction?

Q. $Al$ and $KCl{O}_3$ react together to form $A{I}_2{O}_3$ according to the following reaction:
$2KCl{O}_3⟶2KCl+3O_2$
$4Al+3O_2⟶2A{l}_2{O}_3$
$4$ moles of $KCl{O}_3$ ($50\%$ pure) on reaction with excess of $Al$ forms $A{l}_2{O}_3$ equal to :

Q. $Al$ and $KCl{O}_3$ react together to form $A{l}_2{O}_3$ as follows:
$2KCl{O}_3⟶2KCl+3O_2$
$4Al+3O_2⟶2A{l}_2{O}_3$
$4$ moles of $KCl{O}_3$ ($50\%$ pure) on reaction with excess of $Al$ forms x moles of $A{l}_2{O}_3$. The value of x (as nearest integer) is:

Q. $4Al+3O_2\to 2A{l}_2{O}_3$ In the above equation, identify the oxidising agent

Q. Which of the following is/are combination reaction(s)?
(i) $2KCl{O}_3\stackrel{Heat}{\to }2KCl+3O_2$
(ii) $MgO+H_{2}O\to Mg(OH{)}_2$
(iii) $4Al+3O_2\to 2A{l}_2{O}_3$
(iv) $Zn+FeS{O}_4\to ZnS{O}_4+Fe$