What is the smallest number that when divided by 35 , 36 and 91 leaves remainder 7 in each case?

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Solution

35=5×7

36=2^2 × 3^2

91=7×13

So,LCM(35,36,91)=2^2 × 3^2 ×5×7×13 =36×35×13=36×455=16380

Hence required number =16380+7=16387

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What is the smallest number that, when divided by 35,56 and 91 leaves remainder of 7 in each case

What is the smallest number that when divided by 35, 56 and 91 leaves remainders of 7 in each case?

What is the smallest number that when we divide by 35,56 and 91 leaves remainder in each case.

35, 56

91

7

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