What is the state of CuSO4 and FeSO4 ?

Open in App

Solution

In fact the state of compound depends on the reaction how it was formed.
It can be of liquid state, aqueous state or molten state.
For eg :
In this reaction, the physical states are as follows

CuSO4 (aq.) + Fe (s) --> FeSO4 (aq.) + Cu (s)

Suggest Corrections

Similar questions

C u S O_{4} + F e \to F e S O_{4} + C u

F e S O_{4} + Z n \to Z n S O_{4} + F e

C u S O_{4} + F e \to F e S O_{4} + C u

F e S O_{4} + Z n \to Z n S O_{4} + F e

C u S O_{4}

C u S O_{4} + F e \to F e S O_{4} + C u

C u S O_{4}

F e + C u S O_{4} ⇌ F e S O_{4} + C u

25^{0}

F e + C u S O_{4} ⇌ F e S O_{4} + C u

25^{o} C

E^{0} [F e \to F e^{2 +}) = 0.44 V

E^{0} (C u \to C u^{2 +}) = - 0.337 V

Join BYJU'S Learning Program