When 12.2 g of benzoic acid is dissolved in 100 g of water, the freezing point of solution was found to be $-{0.93}^{o}C\left(K_f\right(H_{2}O)=1.86Kkgmo{l}^{-1})$. Then the number (n) of benzoic acid molecules associated (assuming 100% association) is

Q. 12.2 g of benzoic acid (Mw =122) in 100 g benzene has depression in freezing point ${2.6}^o$, $K_f=5.2{}^{o}Ckg{mol}^{-1}$. If there is 100% polymerization, the number of molecules of benzoic acid in associated state is:

Q. 12.2 g of benzoic acid (Mw=122) in 100 g water has elevation in the boiling point of 0.27. $K_b=0.54Kkg{mol}^{-1}$. If there is 100% polymerization, the number of molecules of benzoic acid in the associated state is:

Q. If benzoic acid (mol. mass = 122) is associated into double molecules when dissolved in benzene and the osmotic pressure of a solution of 5 g of benzoic acid in 100 mL benzene is 5.73 atm at ${10}^{o}C$, what is the percentage association of benzoic acid?

Q. 12.2 g of benzoic acid (Mw = 122) in 100 g water has elevation in boiling point of $\mathrm{0.27.}{K}_b=0.54Kkgmo{l}^{-1}$. If there is 100% polymerization, the number of molecules of benzoic acid in associated state is

Q. Molecules of benzoic acid $\left(C_6{H}_{5}COOH\right)$ dimerise in benzene. '$w$' g of the acid dissolved in $30$g of benzene shows a depression in freezing point equal to $2$K. If the percentage association of the acid to form a dimer in the solution is $80$, then $w$ is: