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Volume of Gases and Number of Moles

When 20 mL of...

Question

When 20 mL of a sample of ozonised oxygen is passed through silent electric discharge, 15 mL of pure ozone gas is obtained. What was the volume of ozone in the original sample?

A

5 mL

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B

10 mL

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C

15 mL

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D

18 mL

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Solution

The correct option is A 5 mL
$3 O_{2} ⟶ 2 O_{3}$
After conversion, total $O_{3} = 15$
Let $x$ be $O_{3}$ in original sample, then $O_{2}$ in original sample= $(20 - x) m l$
Hence, $(15 - x) m l$ $O_{3}$ will be formed.
$O_{2}$ required= $\frac{3}{2} \times$ ( $O_{3}$ formed)
$\Rightarrow 20 - x = \frac{3}{2} (15 - x)$
$\Rightarrow x = 5 m l$

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