An element having configuration $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{1}$ will form_.

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Solution

Basic oxide
According to a given configuration, the last electron is in the $s$ subshell so it belongs to $s$ block elements.
The given electronic configuration is for the element potassium.
So, the element is a metal and metal forms always basic oxide.
Basic oxide reacts with acids to form water and salt.
Example
The basic oxide form of Potassium is $K_{2} O$ .
Hence, an element having configuration $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{1}$ will form basic oxide.

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