Which has more number of atoms,100 g of silver or 100 g of iron?
(Atomic masses:Fe=56u,Ag=108u).

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Solution

$Number of moles of Ag = \frac{Mass of silver (g)}{Molar mass of silver (g / mol)} = \frac{100}{108} = 0.926 mole Number of moles of Fe = \frac{Mass of iron (g)}{Molar mass of iron (g / mol)} = \frac{100}{56} = 1.786 mole Therefore, we find that 100 grams of iron contain 1.786 moles of atoms whereas 100 grams of silver contains 0.926 moles of atoms . Since greater the number of moles, greater is the number of atoms present . As 1.786 > 0.926, Hence, iron will contain greater number of atoms than silver atom .$

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