Which of the following represents the preparation of superphosphate of lime from fluoroapatite- Ca-3-PO-4-2-CaF-2-6H-2PO-4 - 4Ca-H-2PO-4-2- - 2HF - Ca-3-PO-4-2-CaF-2-4H-2SO-4 - 4CaSO-4-2H-3PO-4 - 2HF - 3-Ca-3-PO-4-2-CaF-2-7H-2SO-4 - 3Ca-H-2PO-4-2 - 7CaSO-4-2HF - Ca-3-PO-4-2-3H-3PO-4 - 3Ca-HPO-4-2-

The correct option is C 3[Ca_3(PO_4)'_2+CaF_2]+7H_2SO_4 → 3Ca(H_2PO_4)_2 + 7CaSO_4+2HF ↑ Superphosphate of lime is prepared by treating phosphate rock or f ...

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Byju's Answer

Standard XII

Chemistry

Calcination

Which of the ...

Question

Which of the following represents the preparation of superphosphate of lime from fluoroapatite?

C a_{3} (P O_{4})_{2} + C a F_{2} + 6 H_{2} P O_{4} \to 4 C a (H_{2} P O_{4})_{2}^{'} + 2 H F ↑

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C a_{3} (P O_{4})_{2}^{'} + C a F_{2} + 4 H_{2} S O_{4} \to 4 C a S O_{4} + 2 H_{3} P O_{4} + 2 H F ↑

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3 [C a_{3} (P O_{4})_{2}^{'} + C a F_{2}] + 7 H_{2} S O_{4} \to 3 C a (H_{2} P O_{4})_{2} + 7 C a S O_{4} + 2 H F ↑

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C a_{3} (P O_{4})_{2} + 3 H_{3} P O_{4} \to 3 C a (H P O_{4})_{2}

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Solution

The correct option is C $3 [C a_{3} (P O_{4})_{2}^{'} + C a F_{2}] + 7 H_{2} S O_{4} \to 3 C a (H_{2} P O_{4})_{2} + 7 C a S O_{4} + 2 H F ↑$
Superphosphate of lime is prepared by treating phosphate rock or fluorapatite or bone ash with calculated quantity of conc. $H_{2} S O_{4}$ .
$3 [C a_{3} (P O_{4})_{2}^{'} + C a F_{2}] + 7 H_{2} S O_{4} \to 3 C a (H_{2} P O_{4})_{2} + 7 C a S O_{4} + 2 H F ↑$

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Similar questions

Q. Which of the following is/are correct statement(s) ?
(I)

C a^{2 +}

ions are important in blood clotting.
(II)

C a_{3} (P O_{4})_{2}

is a part of bones.
(III)

3 C a_{3} (P O_{4}) . C a F_{2}

is a part of enamel of teeth.

Q. One equivalent of calcium phosphate,

C a_{3} (P O_{4})_{2}

is dissolved in

H C l

C a_{3} (P O_{4})_{2} + 6 H C l \to 3 C a C l_{2} + 2 H_{3} P O_{4}

Moles of

C a C l_{2}

formed are

\frac{1}{x}

. Then, the value of

x

is:

Q. Complete the following equation.

X e F_{6} + H_{2} O

\to

____

+ 2 H F

X e F_{6} + H_{2} O ⇌ X e O F_{4} + 2 H F

constant

= k_{1}, X e O_{4} + X e F_{6} ⇌ X e O F_{4} + X e O_{3} F_{2}

constant

= K_{2}

. Then equilibrium constant for the following reaction will be:

X e O_{4} + 2 H F ⇌ X e O_{3} F_{2} + H_{2} O

X e F_{6} + H_{2} O ⇌ X e O F_{4} + 2 H F

constant

= K_{1}, X e O_{4} + X e F_{6} ⇌ X e O F_{4} + X e O_{3} F_{2}

. constant

= K_{2}

. Then equilibrium constant for the following reaction will be:

- X e O_{4} + 2 H F ⇌ X e O_{4} F_{2} + H_{2} O

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Which of the following represents the preparation of superphosphate of lime from fluoroapatite?

The correct option is C 3[Ca3(PO4)′2+CaF2]+7H2SO4→3Ca(H2PO4)2+7CaSO4+2HF↑Superphosphate of lime is prepared by treating phosphate rock or fluorapatite or bone ash with calculated quantity of conc. H2SO4.3[Ca3(PO4)′2+CaF2]+7H2SO4→3Ca(H2PO4)2+7CaSO4+2HF↑