Which one of the following has maximum number of atoms?

1 g of Mg(s)

[Atomic mass of

Mg = 24

]

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{1 g of O}_{2} (g)

[Atomic mass of

O = 16

]

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1 g of Li(s)

[Atomic mass of

Li = 7

]

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1 g of Ag(s)

[Atomic mass of

Ag = 108

]

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Solution

The correct option is C $1 g of Li(s)$ [Atomic mass of $Li = 7$ ]
$(a)$ Number of $Mg$ atoms = $\frac{1}{24} \times N_{A}$
$(b)$ Number of $O$ atoms = $\frac{1}{32} \times 2 \times N_{A}$
$(c)$ Number of $Li$ atoms = $\frac{1}{7} \times N_{A}$
$(d)$ Number of $Ag$ atoms = $\frac{1}{108} \times N_{A}$
Hence, the correct answer is option (c).

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