Write a chemical equation of the reaction of ethanoic acid with sodium carbonate.

The reaction of Ethanoic acid $\left({\mathrm{CH}}_3\mathrm{COOH}\right)$ with Sodium carbonate $\left({\mathrm{Na}}_2{\mathrm{CO}}_3\right)$ to liberates Carbon dioxide $\left({\mathrm{CO}}_2\right)$ along with the formation of Sodium acetate $\left({\mathrm{CH}}_3\mathrm{COONa}\right)$ and water.

Chemical reaction

The chemical equation of the reaction of Ethanoic acid with Sodium carbonate is written as:

$$\begin{gathered} 2{\mathrm{CH}}_3\mathrm{COOH}+{\mathrm{Na}}_2{\mathrm{CO}}_3\to 2{\mathrm{CH}}_3\mathrm{COONa}+{\mathrm{CO}}_2+{\mathrm{H}}_2\mathrm{O} \\ (\mathrm{Ethanoic}(\mathrm{Sodium}(\mathrm{Sodium}(\mathrm{Carbon}\left(\mathrm{Water}\right) \\ \mathrm{acid})\mathrm{carbonate})\mathrm{acetate})\mathrm{dioxide}) \end{gathered}$$