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Question
Write nuclear reaction equations for(i) α-decay of 22688 Ra (ii) α-decay of 24294 Pu(iii) β–-decay of 3215 P (iv) β–-decay of 21083 Bi(v) β+-decay of 116 C (vi) β+-decay of 9743 Tc(vii) Electron capture of 12054 Xe
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Solution
In alpha decay the mass number is reduced by four and the atomic number by two R 86 224 a .
P 92 238 u
In beta minus decay the P 15 32 → S 16 32 + β − 1 0
B 83 210 i → P 84 210 o + β − 1 0
After beta plus decay C 6 11 → B 5 11 + β 1 0 +
After beta plus decay T 43 97 c → M 42 97 o
When the electron is captured by the xenon then
X 54 12 e + e − 1 → I 53 120
In alpha decay the mass number is reduced by four and the atomic number by two
In beta minus decay the
After beta plus decay
After beta plus decay
When the electron is captured by the xenon then
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