0.7 g of iron reacts directly with 0.4 g of sulphur to form ferrous sulphide. If 2.8 g of iron dissolves in dilute HCl and excess of sodium sulphide solution is added, 4.4 g of iron sulphide is precipitated. If it obeys the law of constant composition, what is the ratio of weights of Fe : S ?

Q.

What is the maximum concentration of equimolar solutions of ferrous sulphate and sodium sulphide so that when mixed in equal volumes, there is no precipitation of iron sulphide? (For iron sulphide, K_sp = 6.3 × 10^–18).

Q.

0.7 g of iron reacts directly with 0.4 g of sulphur to form ferrous sulphide. If 2.8 g f iron dissolves in dilute HCl and excess of sodium sulphide solution is added, 4.4 g of iron sulphide is precipitated. If it obeys the law of constant composition, what is the ratio of weights of Fe : S ?

Q. 0.7 g of iron combine directly with 0.4 g of sulphur to form FeS . If 2.8g of Fe are dissolved in dil. HCl and excess of sodium sulphide sol is added , 4.4 g of FeS are precipitated . Show that this proves the law of constant proportion

Q.

What is the mass of sulphur that would react with 5 g of iron to form ferrous sulphide $\left(FeS\right)$?

Q. What is the maximum concentration of an equimolar solution of ferrous sulphate$\left(FeS{O}_4\right)$ and sodium sulphide $\left(N{a}_{2}S\right)$ so that when mixed in equal volumes, there is not precipitation of iron sulphide $\left(FeS\right)$?
(For FeS, $K_{sp}=5\times {10}^{-18}$)