6
Question
−1[a−3{b−4(a−¯¯¯¯¯¯¯¯¯¯¯¯b−8)+4a}+10] equals
−1[a−3{b−4(a−¯¯¯¯¯¯¯¯¯¯¯¯b−8)+4a}+10] equals
−a+15b+106
−a+15b−106
−a−15b−106
a+15b−106
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Solution
The correct option is B −a+15b−106
−1[a−3{b−4(a−¯¯¯¯¯¯¯¯¯¯¯¯b−8)+4a}+10]
= −1[a−3{b−4(a−b+8)+4a}+10]
= −1[a−3{b−4a+4b−32+4a}+10]
= −1[a−3{5b−32}+10]
= −1[a−15b+96+10]
= −1[a−15b+106]
= −a+15b−106
−a+15b−106
−1[a−3{b−4(a−¯¯¯¯¯¯¯¯¯¯¯¯b−8)+4a}+10]
= −1[a−3{b−4(a−b+8)+4a}+10]
= −1[a−3{b−4a+4b−32+4a}+10]
= −1[a−3{5b−32}+10]
= −1[a−15b+96+10]
= −1[a−15b+106]
= −a+15b−106
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