(1) Calculate the amount of carbon dioxide that could be produced when
$A)$ $1mole$ of carbon is burnt in air.

(2) Calculate the amount of carbon dioxide that could be produced when
$B)$ $1mole$ of carbon is burnt in $16g$ of dioxygen.

(3) Calculate the amount of carbon dioxide that could be produced when
$C)$ $2mole$ of carbon are burnt in $16g$ of dioxygen.

$1)$ Amount of carbon dioxide:

Description
According to $1^{st}$ question -

$1mole$ of carbon is burnt in air (dioxygen) to produced $1mole$ of carbon dioxide. In this reaction carbon is in limited quantity so, it is limiting reagent

We know, 𝑁𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑚𝑜𝑙𝑒 $=\frac{Mass}{\text{Molar Mass}}$

𝑆𝑜 𝑡ℎ𝑒 𝑎𝑚𝑜𝑢𝑛𝑡 𝑜𝑓 $C{O}_2$ 𝑝𝑟𝑜𝑑𝑢𝑐𝑒𝑑$=44\times 1=44g$

$2)$ Amount of carbon dioxide:

Description

According to $2^{nd}$ question:

$1mole$ of carbon is burnt in $16g$ of dioxygen means $0.5mole$ of dioxygen

Number of mole$=\frac{Mass}{\text{Molar mass}}$

So, have dioxygen is a limiting reagent

So,$0.5mole$ of $O_2$ react with $0.5mole$ of $C{O}_2$

So the amount of $C{O}_2$ produced =no.of mole $\times$ Molar mass$=0.5\times 44=22g$

$3)$ Amount of carbon dioxide:

Description.

According to $3^{rd}$ question :

$2moles$ of carbon are burnt in $16g$ of dioxygen means $0.5mole$ of dioxygen.

𝑁𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑚𝑜𝑙𝑒$=\frac{Mass}{\text{Molar Mass}}$

Here, dioxygen is limiting reagent

So, the amount of $C{O}_2$ produced by $0.5mole$ of $O_2=0.5\times 44=22g$

Final answer:

$\left(i\right)$ Amount of carbon dioxide is $44g$

$\left(ii\right)$ Amount of carbon dioxide is $22g$

$\left(iii\right)$ Amount of carbon dioxide is $22g$