$1cc{N}_{2}O$ at $NTP$ contains _____.

The correct option is D All the above
At NTP,
$1\text{mol}{N}_{2}O=22400cc{N}_{2}O=6.02\times {10}^{23}{N}_{2}O$
$1cc\text{of}{N}_{2}O=\frac{6.02\times {10}^{23}}{22400}$ molecules
Each $N_{2}O$ molecule contains $3$ atoms,
Hence,
$1cc{N}_{2}O=\frac{3\times 6.02\times {10}^{23}}{22400}=\frac{1.8\times {10}^{24}}{22400}$
Nitrogen contains $7$ electrons with $O$ contains $8$ electrons. Hence, the number of electrons in one molecule of $N_{2}O$ is $22$.
Hence,
Number of electrons in $1cc{N}_{2}O$
$=\frac{6.02\times {10}^{23}}{22400}\times 22=\frac{1.32}{224}\times {10}^{23}$ electrons