1 ml of 13.6 M HCl is diluted with water to give 1 litre of the solution. Calculate Ph of the resulting solution.
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Solution
Moles of HCl in the original solution =0.001×13.6=0.0136 moles. Now concentration of HCl in 1 liter solution =0.01361=0.0136M Concentration of H+ = 0.0136M pH=−log[H+]=−log(0.0136)=1.886