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Question

10 kg ball is dropped from a height of 10 m. What is the speed of the ball just before it reaches the ground?


A

14 m/s

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B

20 m/s

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C

35 m/s

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D

21 m/s

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Solution

The correct option is A

14 m/s


At the height of 10 m, the potential energy = mgh

10 kg x 9.8 m/s2 x 10 m = 980 J

Now, let the speed of the ball just before it reaches the ground be v

Then, kinetic energy = 1/2 x mv2

980 = 1/2 x 10 x v2

v = 14 m/s


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