10 mL of a solution of NaOH is found to be completely neutralized by 8 mL of a given solution of HCl. If we take 20 mL of the same solution of NaOH, the amount of HCl solution (the same solution as before) required to neutralize it will be.

The correct option is D

16 ml

$\underset{\mathrm{Hydrochloric}\mathrm{acid}}{\mathrm{HCl}(\mathrm{aq}.)}+\underset{\mathrm{Sodium}\mathrm{Hydroxide}}{\mathrm{NaOH}(\mathrm{aq}.)}\to \underset{\mathrm{Sodium}\mathrm{Chloride}}{\mathrm{NaCl}(\mathrm{aq}.)}+\underset{\mathrm{Water}}{{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right)}$

10 mL of a solution of NaOH completely neutralized by 8 mL of a solution of HCl.

20 mL of a solution of NaOH completely neutralized by 16 mL of a solution of HCl.

Hence, Option(D) is correct.