100ml of 1M NaOH is mixed with 50ml of1N KOH solution . What is Normality of mixture?

We konw that the equvalent normality of a solution is

NV=N1V1+N2V2

Normality(N) = Molarity(M) x number of equivalents

For both NaOH and KOH no.of equivalents =1

Net volume v= 100+50=150

150xN= 1x1(100) +50*1( Since normality of KOH is already goven in the question)

=>N= 150/150 = 1